Matematika Sekolah Dasar Soal:
1.24 cm 18 cm 35 cm Pertanyaan:Volume=......cm³
2. 15 cm 28 cm 42 cm Pertanyaan=.......cm³
3. 20cm 15cm 37cm Pertanyaan=......cm³
4. 16cm 6cm 10² cm 20cm Pertanyaan=.....cm³
5.10cm 75cm 14cm 12,5cm Volume=....cm³
6.20cm 46cm 25cm Pertanyaan=.....cm³
semoga faham:v
NOTE:
10²=10x10 ya kak​

Soal:
1.24 cm 18 cm 35 cm Pertanyaan:Volume=......cm³
2. 15 cm 28 cm 42 cm Pertanyaan=.......cm³
3. 20cm 15cm 37cm Pertanyaan=......cm³
4. 16cm 6cm 10² cm 20cm Pertanyaan=.....cm³
5.10cm 75cm 14cm 12,5cm Volume=....cm³
6.20cm 46cm 25cm Pertanyaan=.....cm³
semoga faham:v
NOTE:
10²=10x10 ya kak​

1)

( 1/2 × 24cm × 18cm ) × 35 cm

= 216 cm² × 35 cm

= 7506

2)

( 1/2 × 15 cm × 28 cm ) × 42 cm

= 210 cm² × 42 cm

= 8820 cm³

3)

( 1/2 × 15 cm × 20 cm ) × 37 cm

= 150 cm² × 37 cm

= 5550 cm³

4)

( 1/2 × 16 cm × 6 cm ) × 20 cm

= 48 cm² × 20 cm

= 960 cm³

5)

( 1/2 × 10 cm × 7,5 cm ) × 14 cm

= 37,5 cm² × 14 cm

= 525 cm³

6)

( 1/2 × 25 cm × 20 cm ) × 46 cm

= 250 cm² × 46 cm

= 11500

▪︎KOREKSI!▪︎

Jawab:

1.) Volume = Luas Alas × Tinggi Prisma

= ([tex]\frac{1}{2}[/tex] × 18 × 24) × 35

= ([tex]\frac{1}{2}[/tex] × 432) × 35

= 216 × 35

= 7.560 cm³

2.) Volume = Luas Alas × Tinggi Prisma

= ([tex]\frac{1}{2}[/tex] × 28 × 15) × 42

= ([tex]\frac{1}{2}[/tex] × 420) × 42

= 210 × 42

= 8.820 cm³

3.) Volume = Luas Alas × Tinggi Prisma

= ([tex]\frac{1}{2}[/tex] × 15 × 20) × 37

= ([tex]\frac{1}{2}[/tex] × 300) × 37

= 150 × 35

= 5.550 cm³

4.) Volume = Luas Alas × Tinggi Prisma

= ([tex]\frac{1}{2}[/tex] × 16 × 6) × 20

= ([tex]\frac{1}{2}[/tex] × 96) × 20

= 48 × 20

= 960 cm³

5.) Volume = Luas Alas × Tinggi Prisma

= ([tex]\frac{1}{2}[/tex] × 10 × 75) × 14

= ([tex]\frac{1}{2}[/tex] × 750) × 14

= 375 × 14

= 5.250 cm³

6.)

Sisi Alas² = Sisi Miring² - Tinggi²

= 25² - 20²

= 225

Sisi Alas = √225

= 15 cm

Volume = Luas Alas × Tinggi Prisma

= ([tex]\frac{1}{2}[/tex] × 15 × 20) × 46

= ([tex]\frac{1}{2}[/tex] × 300) × 46

= 150 × 46

= 6.900 cm³

Semoga Membantu, Maaf Sebesar-Besarnya Kalau Salah ..

[answer.2.content]